Optimal. Leaf size=100 \[ \frac{\left (3 a^2+2 b^2\right ) \sec (c+d x)}{2 d}-\frac{\left (3 a^2+2 b^2\right ) \tanh ^{-1}(\cos (c+d x))}{2 d}-\frac{a^2 \csc ^2(c+d x) \sec (c+d x)}{2 d}+\frac{2 a b \tan (c+d x)}{d}-\frac{2 a b \cot (c+d x)}{d} \]
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Rubi [A] time = 0.25142, antiderivative size = 124, normalized size of antiderivative = 1.24, number of steps used = 10, number of rules used = 9, integrand size = 29, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.31, Rules used = {2911, 2620, 14, 3201, 446, 78, 51, 63, 206} \[ \frac{\left (3 a^2+2 b^2\right ) \sec (c+d x)}{2 d}-\frac{\left (3 a^2+2 b^2\right ) \sqrt{\cos ^2(c+d x)} \sec (c+d x) \tanh ^{-1}\left (\sqrt{\cos ^2(c+d x)}\right )}{2 d}-\frac{a^2 \csc ^2(c+d x) \sec (c+d x)}{2 d}+\frac{2 a b \tan (c+d x)}{d}-\frac{2 a b \cot (c+d x)}{d} \]
Antiderivative was successfully verified.
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Rule 2911
Rule 2620
Rule 14
Rule 3201
Rule 446
Rule 78
Rule 51
Rule 63
Rule 206
Rubi steps
\begin{align*} \int \csc ^3(c+d x) \sec ^2(c+d x) (a+b \sin (c+d x))^2 \, dx &=(2 a b) \int \csc ^2(c+d x) \sec ^2(c+d x) \, dx+\int \csc ^3(c+d x) \sec ^2(c+d x) \left (a^2+b^2 \sin ^2(c+d x)\right ) \, dx\\ &=\frac{(2 a b) \operatorname{Subst}\left (\int \frac{1+x^2}{x^2} \, dx,x,\tan (c+d x)\right )}{d}+\frac{\left (\sqrt{\cos ^2(c+d x)} \sec (c+d x)\right ) \operatorname{Subst}\left (\int \frac{a^2+b^2 x^2}{x^3 \left (1-x^2\right )^{3/2}} \, dx,x,\sin (c+d x)\right )}{d}\\ &=\frac{(2 a b) \operatorname{Subst}\left (\int \left (1+\frac{1}{x^2}\right ) \, dx,x,\tan (c+d x)\right )}{d}+\frac{\left (\sqrt{\cos ^2(c+d x)} \sec (c+d x)\right ) \operatorname{Subst}\left (\int \frac{a^2+b^2 x}{(1-x)^{3/2} x^2} \, dx,x,\sin ^2(c+d x)\right )}{2 d}\\ &=-\frac{2 a b \cot (c+d x)}{d}-\frac{a^2 \csc ^2(c+d x) \sec (c+d x)}{2 d}+\frac{2 a b \tan (c+d x)}{d}-\frac{\left (\left (-3 a^2-2 b^2\right ) \sqrt{\cos ^2(c+d x)} \sec (c+d x)\right ) \operatorname{Subst}\left (\int \frac{1}{(1-x)^{3/2} x} \, dx,x,\sin ^2(c+d x)\right )}{4 d}\\ &=-\frac{2 a b \cot (c+d x)}{d}+\frac{\left (3 a^2+2 b^2\right ) \sec (c+d x)}{2 d}-\frac{a^2 \csc ^2(c+d x) \sec (c+d x)}{2 d}+\frac{2 a b \tan (c+d x)}{d}-\frac{\left (\left (-3 a^2-2 b^2\right ) \sqrt{\cos ^2(c+d x)} \sec (c+d x)\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{1-x} x} \, dx,x,\sin ^2(c+d x)\right )}{4 d}\\ &=-\frac{2 a b \cot (c+d x)}{d}+\frac{\left (3 a^2+2 b^2\right ) \sec (c+d x)}{2 d}-\frac{a^2 \csc ^2(c+d x) \sec (c+d x)}{2 d}+\frac{2 a b \tan (c+d x)}{d}+\frac{\left (\left (-3 a^2-2 b^2\right ) \sqrt{\cos ^2(c+d x)} \sec (c+d x)\right ) \operatorname{Subst}\left (\int \frac{1}{1-x^2} \, dx,x,\sqrt{\cos ^2(c+d x)}\right )}{2 d}\\ &=-\frac{2 a b \cot (c+d x)}{d}+\frac{\left (3 a^2+2 b^2\right ) \sec (c+d x)}{2 d}-\frac{\left (3 a^2+2 b^2\right ) \tanh ^{-1}\left (\sqrt{\cos ^2(c+d x)}\right ) \sqrt{\cos ^2(c+d x)} \sec (c+d x)}{2 d}-\frac{a^2 \csc ^2(c+d x) \sec (c+d x)}{2 d}+\frac{2 a b \tan (c+d x)}{d}\\ \end{align*}
Mathematica [B] time = 0.478155, size = 238, normalized size = 2.38 \[ \frac{\csc ^4(c+d x) \left (-2 \left (3 a^2+2 b^2\right ) \cos (2 (c+d x))-\left (3 a^2+2 b^2\right ) \cos (c+d x) \left (\log \left (\cos \left (\frac{1}{2} (c+d x)\right )\right )-\log \left (\sin \left (\frac{1}{2} (c+d x)\right )\right )\right )+3 a^2 \cos (3 (c+d x)) \log \left (\cos \left (\frac{1}{2} (c+d x)\right )\right )-3 a^2 \cos (3 (c+d x)) \log \left (\sin \left (\frac{1}{2} (c+d x)\right )\right )+2 a^2+8 a b \sin (c+d x)-8 a b \sin (3 (c+d x))+2 b^2 \cos (3 (c+d x)) \log \left (\cos \left (\frac{1}{2} (c+d x)\right )\right )-2 b^2 \cos (3 (c+d x)) \log \left (\sin \left (\frac{1}{2} (c+d x)\right )\right )+4 b^2\right )}{2 d \left (\csc ^2\left (\frac{1}{2} (c+d x)\right )-\sec ^2\left (\frac{1}{2} (c+d x)\right )\right )} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.089, size = 140, normalized size = 1.4 \begin{align*} -{\frac{{a}^{2}}{2\,d \left ( \sin \left ( dx+c \right ) \right ) ^{2}\cos \left ( dx+c \right ) }}+{\frac{3\,{a}^{2}}{2\,d\cos \left ( dx+c \right ) }}+{\frac{3\,{a}^{2}\ln \left ( \csc \left ( dx+c \right ) -\cot \left ( dx+c \right ) \right ) }{2\,d}}+2\,{\frac{ab}{d\sin \left ( dx+c \right ) \cos \left ( dx+c \right ) }}-4\,{\frac{ab\cot \left ( dx+c \right ) }{d}}+{\frac{{b}^{2}}{d\cos \left ( dx+c \right ) }}+{\frac{{b}^{2}\ln \left ( \csc \left ( dx+c \right ) -\cot \left ( dx+c \right ) \right ) }{d}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.0016, size = 166, normalized size = 1.66 \begin{align*} \frac{a^{2}{\left (\frac{2 \,{\left (3 \, \cos \left (d x + c\right )^{2} - 2\right )}}{\cos \left (d x + c\right )^{3} - \cos \left (d x + c\right )} - 3 \, \log \left (\cos \left (d x + c\right ) + 1\right ) + 3 \, \log \left (\cos \left (d x + c\right ) - 1\right )\right )} + 2 \, b^{2}{\left (\frac{2}{\cos \left (d x + c\right )} - \log \left (\cos \left (d x + c\right ) + 1\right ) + \log \left (\cos \left (d x + c\right ) - 1\right )\right )} - 8 \, a b{\left (\frac{1}{\tan \left (d x + c\right )} - \tan \left (d x + c\right )\right )}}{4 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.92053, size = 441, normalized size = 4.41 \begin{align*} \frac{2 \,{\left (3 \, a^{2} + 2 \, b^{2}\right )} \cos \left (d x + c\right )^{2} - 4 \, a^{2} - 4 \, b^{2} -{\left ({\left (3 \, a^{2} + 2 \, b^{2}\right )} \cos \left (d x + c\right )^{3} -{\left (3 \, a^{2} + 2 \, b^{2}\right )} \cos \left (d x + c\right )\right )} \log \left (\frac{1}{2} \, \cos \left (d x + c\right ) + \frac{1}{2}\right ) +{\left ({\left (3 \, a^{2} + 2 \, b^{2}\right )} \cos \left (d x + c\right )^{3} -{\left (3 \, a^{2} + 2 \, b^{2}\right )} \cos \left (d x + c\right )\right )} \log \left (-\frac{1}{2} \, \cos \left (d x + c\right ) + \frac{1}{2}\right ) + 8 \,{\left (2 \, a b \cos \left (d x + c\right )^{2} - a b\right )} \sin \left (d x + c\right )}{4 \,{\left (d \cos \left (d x + c\right )^{3} - d \cos \left (d x + c\right )\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.23266, size = 212, normalized size = 2.12 \begin{align*} \frac{a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + 8 \, a b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 4 \,{\left (3 \, a^{2} + 2 \, b^{2}\right )} \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) \right |}\right ) - \frac{16 \,{\left (2 \, a b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + a^{2} + b^{2}\right )}}{\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 1} - \frac{18 \, a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + 12 \, b^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + 8 \, a b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + a^{2}}{\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2}}}{8 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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